limx→1[sin(x-1)/(x2+x-2)]=()

lim_x→1[sin(x-1)/(x²+x-2)]=()
B、1/3
C、1
D、1/2
【正确答案】：B
【题目解析】：lim_x→1sin(x-1)/(x²+x-2)=lim_x→1sin(x-1)/[(x-1)(x+2)]=lim_x→1sin(x-1)/(x-1)•lim_x→1[1/(x+2)]=1+(1/3)=1/3.